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Seeking help with a curl command in a bash script - SOLVED (lemmy.thewooskeys.com)
submitted 6 months ago* (last edited 6 months ago) by mike_wooskey@lemmy.thewooskeys.com to c/linuxquestions@lemmy.zip
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I've got this command in a bash script:

TEST=$(curl -o /dev/null -s -k -w "%{http_code}" -u "${USERNAME}:${PASSWORD}" "${URL}/dashboard/")
echo "${TEST}" #debug

When the script runs, the output is "000".

When I run the same curl command from the shell, the output is "200" (which is correct, since the URL is valid).

I verified that the USERNAME, PASSWORD, and URL vars are being passed to the subshell.

I'd appreciate it if you could point out what I'm doing wrong here. :)

UPDATE: This has been solved.

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[-] ignoble_stigmas@sh.itjust.works 1 points 6 months ago

Try to add -f to ssh command

[-] mike_wooskey@lemmy.thewooskeys.com 2 points 6 months ago

That seems to have done it!

Running the ssh -f... instead of ssh.... & seems to work first time and every time.

It makes it so SSH_PID=$! doesn't work, but I used pgrep -f <ssh command> instead.

Thanks!

[-] ignoble_stigmas@sh.itjust.works 1 points 6 months ago

You are very welcome! That was the hypothesis, that ssh doesn’t go into background as you want it to, since it works for the second run, but tunnel is there after the first.

this post was submitted on 08 Dec 2024
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