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Anon describes past
(lemmy.ml)
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this post was submitted on 13 May 2025
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If you want to get real nerdy about it this works because the natural logarithm of 2 is ~0.69
(1+i)^n = 2
n log (1+i) = log 2
n = log 2 / log (1+i)
For small numbers, log(1+x) ≈ x
n ≈ log 2/i
log 2 ≈ 0.69
n ≈ 0.69 / i
n ≈ 69/100i
Which is pretty close to 70/100i which is the approximation.
that is pretty nerdy, but I appreciate the thorough explanation