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[-] ferric_carcinization@lemmy.ml 18 points 1 day ago* (last edited 1 day ago)

The compiler should be able to optimize all of them to the same machine code.

  1. This is already good.
  2. Easily optimized by constant folding.
  3. ~~This one depends on the semantics of signed underflow, so it may not do what you want.~~
  4. ~~The loop can only exit if x==10, so as long as the nextInt() method doesn't have side effects, the loop should be eliminated. But, again, language semantics can affect this.~~

Edit: Very wrong for 3 & 4, see replies.

[-] ryannathans@aussie.zone 18 points 1 day ago

I'd be shocked if 4 got optimised out

[-] Mio@feddit.nu 11 points 1 day ago
  1. It is used to warm up the house.
[-] MangoCats@feddit.it 3 points 1 day ago

4 is used for non-deterministic delay - - - is Random.nextInt() also cryptographically secure?

[-] ferric_carcinization@lemmy.ml 2 points 1 day ago

I feel like an idiot. Also, in the "Good" example, no underflow occurs. i goes from 0 to -10, and x is assigned to -i every loop.

It might still be possible to optimize away the random number example, if the random function were made a magic language item, but it would not be even remotely close to being worth the effort.

[-] MangoCats@feddit.it 2 points 1 day ago

The question the optimizer can't really answer is: will Random.nextInt() ever return 10? If that's a 64 bit integer it could be a LOOOOOONG time before 10 ever shows up.

[-] ferric_carcinization@lemmy.ml 1 points 21 hours ago

If it were a magic lang item, you could treat the resulting value in a special way. Then, you could create an optimization pass for this situation: if a variable is assigned random in a loop and the loop can only be exited with a certain value, the compiler can coerce the magic rand value to it.

[-] ryannathans@aussie.zone 1 points 1 day ago

Ah yes the halting problem

[-] MimicJar@lemmy.world 6 points 1 day ago

For #4 if the Random instance weren't "new", then calling the nextInt() function would definitely have side effects, since the next integer would pull one away from the random stack.

However unlike the first three which will run within a consistent amount of time, #4 will take an unknown amount of time to run, so you can't just collapse it and eliminate the loop.

For example a very simple race game where a participant moves a random number of steps each turn, we may want to time how long that race takes. We can't just say that they will reach the end immediately. In fact technically we don't know that they will ever finish the race... But that's the halting problem and a whole other issue.

[-] ferric_carcinization@lemmy.ml 3 points 1 day ago

I don't know what I was thinking.

But, if you borrow C's semantics, you are allowed to "optimize" away side-effect-less loops, even if they would never terminate. But that would require the random method to be pure.

[-] pineapple@lemmy.ml 2 points 1 day ago

Still a mess to read though, anyone revewing the code will be like wtf?

this post was submitted on 13 Dec 2025
267 points (97.8% liked)

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