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[-] quilan@lemmy.world 1 points 1 month ago

But of course -- It's just flipping around the -= operator!

[-] squaresinger@lemmy.world 3 points 1 month ago

Nope, it is not.

x = 5
i = 2
x -= i // x => 3

while

x = 5
i = 2
x = -i // x => -2

x=-i is the unary minus operator which negates the value right of it. It doesn't matter if that value is a literal (-3), a variable (-i) or a function (-f()).

x-=i is short for x = x-i, and here it's a binary subtraction, so x is set to the result of i subtracted from x.

[-] quilan@lemmy.world 2 points 1 month ago

I need to append /s to my future silly replies I think... that said, I'll never pooh-pooh a well thought response, so thanks for the nice write-up!

[-] squaresinger@lemmy.world 2 points 1 month ago* (last edited 1 month ago)

Thanks, I totally missed your sarcasm :)

There's a couple people in this threat who seem to actually think that x = -i is some weird magic instead of a standard feature that's present in every major programming language.

[-] spongebue@lemmy.world 1 points 1 month ago* (last edited 1 month ago)

That only works if x is already 0

If i is 10 and x is zero, yes, x -= i would have a value of -10. If x was 5 from something else previously, x-=i would end with an x value of -5.

this post was submitted on 13 Dec 2025
652 points (97.7% liked)

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