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submitted 1 year ago* (last edited 1 year ago) by wulf@lemmy.world to c/programming@programming.dev

Background: I have a large serde_json value that I want to be read-only (the authoritative source is an encrypted SQLite DB and should only be updated when that gets updated)

The issue, I would like a single get function that returns a generic type

use serde_json;

pub struct Configuration {
    config: serde_json::Value,
}

impl Configuration {
    async fn get(&self, key: &str) -> Result {
        let tmp_value: = &self.config["test"];

        // This would be repeated for String, bool, etc
        if tmp_value.is_i64() {
            match tmp_value.as_i64 {
                Some(x) => Ok(x),
                Err(e) => Err(()),
            }
        } else {
            Err(())
        }
    }
}

However I get: "mismatched types expected type parameter T found type i64"

Is it even possible to return multiple types from a single function?

EDIT: SOLUTION

Here is the solution I came up with:

pub struct Configuration {}

impl Configuration {
    fn get std::str::FromStr>() -> Result {
        Ok(T::from_str("1234");
    }
}

fn main() {
    let my_conf_val = Configuration::get();
}
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[-] I_like_cats@lemmy.one 13 points 1 year ago

No. You can only return a single type from the function. You could return the serde_json::Value though so that the code calling this function can get the value it needs itself

[-] wulf@lemmy.world 2 points 1 year ago* (last edited 1 year ago)

Afraid this might have been the case, if Ogeon's suggestion doesn't work out, I'll probably end up with multiple getters, one per type. There aren't that many anyway

Thank you!

this post was submitted on 25 Oct 2023
16 points (90.0% liked)

Programming

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