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trick OR treat (media.infosec.exchange)

submitted 1 year ago by Masimatutu@lemm.ee to c/programmerhumor@lemmy.ml

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[-] AntiOutsideAktion@hexbear.net 2 points 1 year ago

pretty sure both work

[-] walthervonstolzing@lemmy.ml 1 points 1 year ago

NAND and XOR aren't equivalent, though

| X | Y | X NAND Y |
| 0 | 0 | 1        |
| 1 | 0 | 1        |
| 0 | 1 | 1        |
| 1 | 1 | 0        |

| X | Y | X XOR Y |
| 0 | 0 | 0       |
| 1 | 0 | 1       |
| 0 | 1 | 1       |
| 1 | 1 | 0       |

& XOR can be reduced to NAND; not sure if NAND can be reduced to XOR

[-] myslsl@mastodon.social 2 points 1 year ago

@walthervonstolzing @AntiOutsideAktion

If ya'll get bored and wanna read more about this, this is a property called functional completeness. I'm pretty sure nand and nor are the only functionally complete binary operators, so xor shouldn't be functionally complete.

https://en.m.wikipedia.org/wiki/Functional_completeness

[-] AntiOutsideAktion@hexbear.net 0 points 1 year ago* (last edited 1 year ago)

pretty sure I meant to say nor

this post was submitted on 27 Oct 2023

1135 points (99.2% liked)

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