Statically Typed Functional Programming with Python 3.12 (wickstrom.tech)

submitted 6 months ago by mao@lemmy.sdf.org to c/python@programming.dev

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Neato

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[-] FizzyOrange@programming.dev 3 points 6 months ago* (last edited 6 months ago)

You're still limited by lambda expressions though. And in general the language is still statement based, not expression based. You can't do a = if foo then x else y type things (except for the one-off and backwards x if foo else y; they were so close!).

[-] nxdefiant@startrek.website 1 points 6 months ago

"a = x if foo else y" is a perfectly cromulent statement!

[-] FizzyOrange@programming.dev 2 points 6 months ago

It's not. In functional languages there's no special case like this. All if-elses are expressions. It's far superior. For example how do you do this with Python's if-else expression?

let x = if foo {
  let y = bar();
  baz();
  y
} else {
  z
}

[-] nxdefiant@startrek.website 1 points 6 months ago

x = foo(y:=bar(), baz(), y) or z should work assuming foo bar and baz are functions being called?

if this is setting y to the effect of bar() + running baz after, then:

x = [bar(), baz()][0] or z

might work

and if you need y to be defined for later use:

x = [(y:=bar()), baz()][0] or z

but thats from memory, not sure if that will even run as written.

if I get to a real computer I'll try that with an actual if statement instead of a bastardized ternary.

[-] FizzyOrange@programming.dev 2 points 6 months ago

foo isn't a function, it's a bool. But in any case, as you can see the answer is "with terrible hacks". Python is not a functional language. It is imperative.