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Why is Go syntax so messy
(lemmy.ca)
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That is absolutely not true.
foo := <expr>
is a statement in Go, full stop. Just try something trivial like assigning to the output of:=
: https://go.dev/play/p/nPINGc7LO8BIt's true that
if
andfor
let you use:=
but don't let you usevar
, but you still can't use the result of the assignment directly. So for instance you needif foo := <expr>; foo { ... }
rather than justif foo := <expr> { ... }
.Ok I see, I stand corrected then. Its a misconception I had without actually going through all of this, so my bad (will edit my replies to mark them). At least in Python we can do this
print(foo := (bar := 3))
but not on its own asfoo := 3
.