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Not everything can be done in constant time, that's O(k) (sh.itjust.works)
submitted 4 months ago by alphacyberranger@sh.itjust.works to c/programmer_humor@programming.dev
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[-] petersr@lemmy.world 23 points 4 months ago

Let me take a stab at it:

Problem: Given two list of length n, find what elements the two list have in common. (we assume that there are not duplicates within a single list)

Naive solution: For each element in the first list, check if it appears in the second.

Bogo solution: For each permutation of the first list and for each permutation of the second list, check if the first item in each list is the same. If so, report in the output (and make sure to only report it once).

[-] victorz@lemmy.world 2 points 4 months ago

lol, you'd really have to go out of your way in this scenario. First implement a way to get every single permutation of a list, then to ahead with the asinine solution. ๐Ÿ˜† But yes, nice one! Your imagination is impressive.

this post was submitted on 22 Jun 2024
404 points (97.4% liked)

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