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[-] cypherix93@lemmy.world 11 points 2 months ago

"strawberry".split('').filter(c => c === 'r').length

[-] SpaceNoodle@lemmy.world 9 points 2 months ago

len([c if c == 'r' for c in "strawberry"])

[-] tiefling@lemmy.blahaj.zone 6 points 2 months ago

'strawberry'.match(/r/ig).length

[-] pkill@programming.dev 2 points 2 months ago

(\r (frequencies "strawberry"))

this post was submitted on 22 Aug 2024
851 points (96.4% liked)

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