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regex and awk...
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this post was submitted on 08 Jun 2025
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Not sure if I'm understanding, but can't you just pipe the whole thing to
awkand capture the first field? Likeecho "/dev/loop0: [2081]:64 (/a/path/to/afile.dat)" | awk -F: '{print $1}'Which would print
/dev/loop0That would also print the colon
Edit: missed the separator token. Sorry guys
No, because we're telling to use
:as a separator with the -F flag