480

timeoutSort (lemmy.ml)

submitted 2 months ago by cm0002@lemmy.world to c/programmer_humor@programming.dev

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[-] zea_64@lemmy.blahaj.zone 20 points 2 months ago

Wait till you find out how the runtime manages multiple concurrent timers

[-] sus@programming.dev 13 points 2 months ago

it's

while (true) {
    let t = Date.now();
    if (timeoutMap.has(t)) timeoutMap[t]();
}

of course. Clearly O(n).

disclaimer

Feel free to use it. I guarantee it is bug free. Comes with express warranty. This notice is legally binding.

[-] FooBarrington@lemmy.world 5 points 2 months ago* (last edited 2 months ago)

I found a way to optimize your code without affecting the result. By making it branchless, I was able to get my CPU to 100% utilization!

[-] yetAnotherUser@lemmy.ca 2 points 2 months ago

Then don't complain once you get arrested...

[-] ulterno@programming.dev 1 points 2 months ago

From nowaday's standards, that's express warranty that lasts until you start executing your code.

this post was submitted on 04 Nov 2025

480 points (99.2% liked)

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