858
6÷2(1+2)
(programming.dev)
I wrote a (very long) blog post about those viral math problems and am looking for feedback, especially from people who are not convinced that the problem is ambiguous.
It's about a 30min read so thank you in advance if you really take the time to read it, but I think it's worth it if you joined such discussions in the past, but I'm probably biased because I wrote it :)
P.S. if you DID want to indicate "weak juxtaposition", then you just put a multiplication symbol, and then yes it would be done as "M" in BEDMAS, because it's no longer the coefficient of a bracketed term (to be solved as part of "B"), but a separate term.
6/2(1+2)=6/(2+4)=6/6=1
6/2x(1+2)=6/2x3=3x3=9