858
6÷2(1+2)
(programming.dev)
I wrote a (very long) blog post about those viral math problems and am looking for feedback, especially from people who are not convinced that the problem is ambiguous.
It's about a 30min read so thank you in advance if you really take the time to read it, but I think it's worth it if you joined such discussions in the past, but I'm probably biased because I wrote it :)
Actually it should be x(y+z)=(xy+xz), as that's exactly where a lot of people go wrong. They go from 6/2(1+2) to 6/2x3, instead of to 6/(2x3), and thus end up with the wrong answer (cos that flipped the 3 from being in the denominator to being in the numerator. i.e. instead of dividing by 3 they are now multiplying by 3, all because they removed brackets prematurely).