1201
Mafs
(sh.itjust.works)
you are viewing a single comment's thread
view the rest of the comments
view the rest of the comments
this post was submitted on 21 Mar 2024
1201 points (98.9% liked)
memes
10326 readers
1226 users here now
Community rules
1. Be civil
No trolling, bigotry or other insulting / annoying behaviour
2. No politics
This is non-politics community. For political memes please go to !politicalmemes@lemmy.world
3. No recent reposts
Check for reposts when posting a meme, you can only repost after 1 month
4. No bots
No bots without the express approval of the mods or the admins
5. No Spam/Ads
No advertisements or spam. This is an instance rule and the only way to live.
Sister communities
- !tenforward@lemmy.world : Star Trek memes, chat and shitposts
- !lemmyshitpost@lemmy.world : Lemmy Shitposts, anything and everything goes.
- !linuxmemes@lemmy.world : Linux themed memes
- !comicstrips@lemmy.world : for those who love comic stories.
founded 1 year ago
MODERATORS
Neatly showing why when all you have is two data points you can't just assume the best fit function for extrapolation is a linear one.
Mind you, a surprisingly large number of political comments is anchored in exactly that logic.
Doubling every three months is an exponential interpolation and not a linear one!
Good point and well spotted!
PS: Though it's not actually called exponential (as it isn't e^nr-3-month-periods^ but rather 2^nr-3-month-periods^ ) but has a different name which I can't recall anymore.
PPS: Found it - it's a "geometric progression".
By tweaking a few parameters you can turn every base into any other base for exponentials. Just use e^(ln(b)*x)
PS: The formula here would be e^(ln(2)/3*X) and x is the number of months. So the behavior it's exponential in nature.
By that definition you can turn any linear function a * x + b, "exponential" by making it e^ln(a*x +b) even though it's actually linear (you can do it to anything, including sin() or even ln() itself, which would make per that definition the inverse of exponential "exponential").
Essentially you're just doing f(f^-1^(g(x))) and then saying "f(m) is e^m^ so if I make m = ln(g(x)) then g(x) is exponential"
Also the correct formula in your example would be e^(ln(2)*X/3) since the original formula if X denotes months is 2^X/3^
It doesn't matter if you divide ln(2) or x by three, it's the same thing.
Get a room you two
A terminology that I learned from the Terminator 2 movie. Only that was, I think, a "geometric rate".
Chessboard and wheat
One of the best mathematical stories from ancient times, IMHO,
It's cold today, so much for climate change 🧐
Close, if you'd instead called it global warming I'd have bought it
Dammit, we're on a cooling trajectory, prepare for a new ice age and the approach to absolute zero by end of year