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this post was submitted on 29 Aug 2024
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Ted Ts'o is a prick with a god complex. I understand his experience is hard to match, we all have something in our lives we're that good at, but that does not need to lead to acting like a fucking religious fanatic.
At some point, that mix of experience and ego becomes a significant liability. He's directly hurting the adoption of Rust in the kernel, while the C code he's responsible for is full of problems that would have been impossible if written in safe Rust.
CVE-2024-42304 — crash from undocumented function parameter invariants
CVE-2024-40955 — out of bounds read
CVE-2024-0775 — use-after-free
CVE-2023-2513 — use-after-free
CVE-2023-1252 — use-after-free
CVE-2022-1184 — use-after-free
CVE-2020-14314 — out of bounds read
CVE-2019-19447 — use-after-free
CVE-2018-10879 — use-after-free
CVE-2018-10878 — out of bounds write
CVE-2018-10881 — out of bounds read
CVE-2015-8324 — null pointer dereference
CVE-2014-8086 — race condition
CVE-2011-2493 — call function pointer in uninitialized struct
CVE-2009-0748 — null pointer dereference
My favourite, as that was the exact point the dev was making in his talk, that the stuff is badly documented and that the function signature would document it perfectly.
My favorite, as that is the exact point made by anti-rust people.
What kind of type signature would prove the first block of any directory in an ext4 filesystem image isn't a hole?
The problem isn't that the block is a hole. It's that the downstream function expects the directory block to contain
.
and..
, and it gets given one without because of incorrect error handling.You can encode the invariant of "has dot and dot dot" using a refinement type and smart constructor. The refined type would be a directory block with a guarantee it meets that invariant, and an instance of it could only be created through a function that validates the invariant. If the invariant is met, you get the refined type. If it isn't, you only get an error.
This doesn't work in C, but in languages with stricter type systems, refinement types are a huge advantage.
Wouldn't it still crash when the smart constructor was called?
If it were poorly designed and used exceptions, yes. The correct way to design smart constructors is to not actually use a constructor directly but instead use a static method that forces the caller to handle both cases (or explicitly ignore the failure case). The static method would have a return type that either indicates "success and here's the refined type" or "error and this is why."
In Rust terminology, that would be a
Result<T, Error>
.For Go, it would be
(*RefinedType, error)
(where dereferencing the first value without checking it would be at your own peril).C++ would look similar to Rust, but it doesn't come as part of the standard library last I checked.
C doesn't have the language-level features to be able to do this. You can't make a refined type that's accessible as a type while also making it impossible to construct arbitrarily.
You can do that in C, too.
You're going to need to cite that.
I'm not familiar with C23 or many of the compiler-specific extensions, but in all the previous versions I worked with, there is no type visibility other than "fully exposed" or opaque and dangerous (
void*
).You could try wrapping your
Foo
inBut nothing stops someone from being an idiot about it and constructing it by hand:
Or even just casting it.
Yes, this is like not checking an error code.
That's not the point, though. The point is to use a nominal type that asserts an invariant and make it impossible to create an instance of said type which violates the invariant.
Both validation functions and refinement types put the onus on the caller to ensure they're not passing invalid data around, but only refinement types can guarantee it. Humans are fallible, and it's easy to accidentally forget to put a
check_if_valid()
function somewhere or assume that some function earlier in the call stack did it for you.With smart constructors and refinement types, the developer literally can't pass an unvalidated type downstream by accident.
I don't know if the type system proves it's not a hole, but the type system certainly seems to force consumers to contend with the possibility by surfacing the outcomes at the type system level. That's what the
Either
is doing in the example's return type, is it not?