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this post was submitted on 03 Sep 2024
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Linux is a family of open source Unix-like operating systems based on the Linux kernel, an operating system kernel first released on September 17, 1991 by Linus Torvalds. Linux is typically packaged in a Linux distribution (or distro for short).
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Here's what I think. Both opinions are correct.
Rust is sufficiently different that you cannot expect C developers to learn rust to the level they have mastered C in order to be working at the kernel level. It's not going to happen.
I don't really know too much about rust. Maybe one day I'll actually mess around with it. But the one time I looked at a rust git repo I couldn't even find where the code to do a thing was. It's just different enough to be problematic that way.
So I think probably, the best way IS to go the way linus did. Just go ahead and write a very basic working kernel in rust. If the project is popular it will gain momentum.
Trying to slowly adapt parts of the kernel to rust and then complain when long term C developers don't want to learn a new language in order to help isn't going to make many friends on that team.
But that's the thing where you are wrong. They clearly state they don't want C developers to learn Rust. In the particular video posted he was saying "I want you to explain to me how this particular API works so that I can do it"
The concerns about who fixes what on a merge when the C code breaks Rust code are valid, but that's easily fixed by gathering with the Rust developers, explaining the changes and letting them fix it.
I've inserted myself into your C project because only idiots write C. Rust is the one true god, mUh MeMoRy sAfteY! Now please explain to me how C works.
LMAO
That's not what they're asking. It's not about how C works, it's about how specific APIs written in C work, which is hard to figure out on your own for anyone who is not familiar with that specific code. You'll have to explain that to any developer coming new into the project expected to work with those APIs, no matter their experience with C.