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Not my problem sort (infosec.pub)
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[-] xmunk@sh.itjust.works 96 points 2 weeks ago

Guaranteed to sort the list in nearly instantaneous time and with absolutely no downsides that are capable of objecting.

[-] frezik@midwest.social 48 points 2 weeks ago

You still have to check that it's sorted, which is O(n).

We'll also assume that destroying the universe takes constant time.

[-] BatmanAoD@programming.dev 43 points 2 weeks ago

In the universe where the list is sorted, it doesn't actually matter how long the destruction takes!

[-] groet@feddit.org 13 points 2 weeks ago

It actually takes a few trillion years but its fine because we just stop considering the "failed" universes because they will be gone soon™ anyway.

[-] MBM@lemmings.world 8 points 2 weeks ago

Eh, trillion is a constant

[-] FiskFisk33@startrek.website 8 points 2 weeks ago

amortized O(0)

[-] Benjaben@lemmy.world 9 points 2 weeks ago

We'll also assume that destroying the universe takes constant time.

Well yeah just delete the pointer to it!

[-] PoolloverNathan@programming.dev 2 points 2 weeks ago

universe.take()

[-] vithigar@lemmy.ca 16 points 2 weeks ago

Except you missed a bug in the "check if it's sorted" code and it ends up destroying every universe.

[-] db2@lemmy.world 7 points 2 weeks ago

There's a bug in it now, that's why we're still here.

[-] frezik@midwest.social 1 points 2 weeks ago

You still have to check that it's sorted, which is O(n).

We'll also assume that destroying the universe takes constant time.

this post was submitted on 08 Nov 2024
751 points (98.2% liked)

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