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submitted 10 months ago by TheGuyTM3@lemmy.ml to c/asklemmy@lemmy.ml

It can look dumb, but I always had this question as a kid, what physical principles would prevent this?

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[-] Pacattack57@lemmy.world 5 points 10 months ago

How heavy would a stick of this size weigh?

[-] TheGuyTM3@lemmy.ml 4 points 10 months ago* (last edited 10 months ago)

We're supposing that you have an herculean strengh and that weight is not a problem

[-] Spzi@lemm.ee 4 points 10 months ago

Weigh on Earth or on Moon?

[-] adaveinthelife@lemmy.ca 5 points 10 months ago

Go find a 30' stick and let us know if you can point it at the moon.

[-] jerkface@lemmy.ca 5 points 10 months ago

Putting it on the moon is just a distraction. It doesn't matter if the rod is 1m long or 100,000km.

[-] GnuLinuxDude@lemmy.ml 4 points 10 months ago

I enjoyed a lot of the discussion in the comments

[-] MithranArkanere@lemmy.world 3 points 10 months ago

That would not work. Pushing an object is transmitting kinetic energy to it. The object will push back, and energy would not be distributed to the whole object at the same time.
If the object cannot be altered in any way, then the energy would not be transferred to it, and if it has enough plasticity to absorb the kinetic energy, it would be spread in a wave to the tip. A wave that would always be slower than light.

Now stop fooling around and give Ruyi Jingu Bang back to Sun Wukong.

[-] echo@lemmings.world 3 points 10 months ago

The pole would basically be a space elevator. I suspect gravity and inertia would effectively keep you from moving the stick. Even if you could move it, you'd only be able to move it at a speed that would seem like it's stationary. As such, the light would still be faster.

[-] fnrir@lemmy.world 3 points 10 months ago* (last edited 10 months ago)

https://youtu.be/6g2bHqV01es

EDIT: It's in Polish, but it's still a good video.

[-] WorldsDumbestMan@lemmy.today 2 points 10 months ago

Nah, I prefer using quantum spookiness for that. Send a steady stream of entangled particles to the other person on the moon first. Any time you do something to the particles on Earth, the ones on the Moon are affected also. The catch is that this disentangles them, so you have only a few limited uses. This is why you want a constant stream of them being entangled.

[-] pcalau12i@lemmygrad.ml 2 points 10 months ago

Any time you do something to the particles on Earth, the ones on the Moon are affected also

The no-communication theorem already proves that manipulating one particle in an entangled pair has no impact at al on another. The proof uses the reduced density matrices of the particles which capture both their probabilities of showing up in a particular state as well as their coherence terms which capture their ability to exhibit interference effects. No change you can make to one particle in an entangled pair can possibly lead to an alteration of the reduced density matrix of the other particle.

[-] InputZero@lemmy.world 2 points 10 months ago

This wouldn't work, entangled particles don't work like that. They would be disentangled the moment you do anything to either particle of the entangled pair. The only time any information can be encoded onto entangled particles is when they're created.

[-] ulterno@programming.dev 2 points 10 months ago* (last edited 10 months ago)

The only time any information can be encoded onto entangled particles is when they’re created.

If that were the case, then we aren't really doing FTL communication, unless we manage to entangle them at a distance. No?

OIC, it's still useful if we want to make a secret key and send it somewhere. Then both sides can take a reading sometime in the future and they can then use whatever cluster of entangled particles they saw, as the symmetric key.

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[-] Ludrol@szmer.info 2 points 10 months ago
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this post was submitted on 11 Feb 2025
522 points (94.2% liked)

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