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[-] tetris11@lemmy.ml 4 points 1 year ago

a clock running backwards is moving away from the current time at twice the rate, so isn't your example the same as saying that a clock that runs twice as fast is right 4 times a day?

[-] ryathal@sh.itjust.works 11 points 1 year ago

No, if you go twice as fast, it would only align with one at 12 and one at 24. It's not about speed, it's about the intersections of forward and backward laps.

[-] tetris11@lemmy.ml 3 points 1 year ago

Can you give me some examples, for some reason I'm finding it hard to picture

[-] ryathal@sh.itjust.works 5 points 1 year ago

You can picture a clock or a track. If you have one going forward and one backwards, they meet at the halfway point (6), and again at the full lap (12). This happens twice in a day.

If you have one going twice as fast, they only meet when the faster one laps the slower one. The two clocks would be at 3&6, 6&12, 9&6(18), 12&12(24)

[-] tetris11@lemmy.ml 3 points 1 year ago

Ah yeah, there it is - thanks for that example

[-] humanspiral@lemmy.ca 1 points 1 year ago

it is less than 4 times/day correct, if there is a speed difference between backward rotation and time.

[-] dQw4w9WgXcQ@lemm.ee 6 points 1 year ago

Ah, shit, a clock that runs infinitely fast is always right.

[-] Dragonborn3810@lemmy.world 1 points 1 year ago

Love your username

[-] davidgro@lemmy.world 1 points 1 year ago

It's also always wrong. Infinities are like that.

this post was submitted on 20 Jan 2025
149 points (98.1% liked)

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