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[-] Acute_Engles@hexbear.net 26 points 10 months ago

Bringing up the fact that Pythagorean theorem doesn't work when one of the known values is √2. Pythagoras really didn't like this

[-] ValpoYAFF@hexbear.net 26 points 10 months ago* (last edited 10 months ago)

The Pythagorean relation ABSOLUTELY holds for a triangle whose legs are both 1 and whose hypotenuse is 2^(1/2). Pythagoras' cult simply didn't believe in irrational numbers, hence their trouble when the Pythagorean relation implied it. It is known there was even a proof at the time of the irrationality of the square root of two.

[-] hexaflexagonbear@hexbear.net 12 points 10 months ago* (last edited 10 months ago)

More specifically, I don't know how advanced the details of mathematical philosphy were at the time. But a discussion point might be that just because irrational numbers are logically possible, doesn't mean they're "real" (in some sense). However, being constructible using basic geometric arguments (as a right angled isolese triangle is) would make arguing against their existence much more difficult.

[-] DayOfDoom@hexbear.net 19 points 10 months ago

New "John Lennon beat his wife" guy just dropped.

[-] FourteenEyes@hexbear.net 11 points 10 months ago

John Lennon stopped beating his wife when the imaginary numbers patch dropped for Pythagorean Theorem™

[-] hexaflexagonbear@hexbear.net 15 points 10 months ago

Pythagorean theorem works, I think you might be confusing this with the fact that the Pythagoreans rejected the notion of irrational numbers, but √2 is the length of the hypotoneuse of a right angle triangle where the other sides are unit length

[-] Acute_Engles@hexbear.net 2 points 10 months ago

3 days late but i would like to recognize that i am wrong

this post was submitted on 22 Jan 2024
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