810
Heh (sh.itjust.works)
submitted 1 year ago by sjmarf@sh.itjust.works to c/memes@lemmy.ml
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[-] AbouBenAdhem@lemmy.world 89 points 1 year ago
[-] adj16@lemmy.world 11 points 1 year ago

😆 nice one

[-] Ryan213@lemmy.world 62 points 1 year ago* (last edited 1 year ago)

I don't understand the formula, but I understand Mr. Bean. +1

[-] Limitless_screaming@kbin.social 29 points 1 year ago

If you have two charges q1 and q2, you can get the force between them F by multiplying them with the coulomb constant K (approximately 9 × 10^9) and then dividing that by the distance between them squared r^2.

q1 and q2 cannot be negative. Sometimes you'll not be given a charge, and instead the problem will tell you that you have a proton or electron, both of them have the same charge (1.6 × 10^-19 C), but electrons have a negative charge.

[-] Kolrami@lemmy.world 20 points 1 year ago

q1 and q2 can be negative. The force is the same as if they were positive because -1 x -1 = 1

[-] Limitless_screaming@kbin.social 4 points 1 year ago

In this case yes, but if q1 was -20μC, q2 was 30μC, and r was 0.5m, then using -20μC as it is would make F equal to -21.6N which is just 21.6N of attraction force between the two charges.

[-] Pelicanen@sopuli.xyz 5 points 1 year ago

If they are oppositely charged particles, I would expect that there is a force of attraction acting on them, yes.

[-] Limitless_screaming@kbin.social 1 points 1 year ago

I am not saying that's wrong, just that there's 21.6N of attraction force between the two charges not -21.6N.

[-] Pelicanen@sopuli.xyz 2 points 1 year ago

But those are the same thing.

[-] Bene7rddso@feddit.de 3 points 1 year ago

No, if the force is negative it acts in the opposite direction

[-] Pelicanen@sopuli.xyz 5 points 1 year ago

Yes, and a force acting in the opposite direction of the distance is an attractive force.

[-] Pinklink@lemm.ee 0 points 1 year ago* (last edited 1 year ago)

But that if both are negative not one pos one neg like the previous commenter gave in their examples, so the true formula has an absolute value in the numerator: |q1Xq2|

[-] Bene7rddso@feddit.de 1 points 1 year ago

No, but there should be a minus in the Coulomb formula

[-] Arthur_Leywin@lemmy.ml 10 points 1 year ago* (last edited 1 year ago)

G is a constant,

m is mass,

d is distance from each other starting from their center of mass,

This measures gravitational force, F

[-] jimmydoreisalefty@lemmus.org 39 points 1 year ago* (last edited 1 year ago)

edit: fix similarities typo

Awesome to see the similarities between: Newtonian Mechanics and Quantum mechanics

Coulomb's law was essential to the development of the theory of electromagnetism and maybe even its starting point, as it allowed meaningful discussions of the amount of electric charge in a particle.

Here, ke is a constant, q1 and q2 are the quantit>ies of each charge, and the scalar r is the distance between the charges.

Being an inverse-square law, the law is similar to Isaac Newton's inverse-square law of universal gravitation, but gravitational forces always make things attract, while electrostatic forces make charges attract or repel. Also, gravitational forces are much weaker than electrostatic forces. Coulomb's law can be used to derive Gauss's law, and vice versa. In the case of a single point charge at rest, the two laws are equivalent, expressing the same physical law in different ways. The law has been tested extensively, and observations have upheld the law on the scale from 10−16 m to 108 m.

[-] Claidheamh@slrpnk.net 24 points 1 year ago

It's electromagnetism you mean, not quantum mechanics.

Guess what electromagnetism turned out to be

[-] Claidheamh@slrpnk.net 20 points 1 year ago

They're different things. The OP means electromagnetism, Coulomb's law has nothing to do with quantum mechanics, it's classical physics.

[-] Natanael@slrpnk.net -3 points 1 year ago

Quantum electrodynamics though

Okay but tell me, what theory superceded electromagnetism?

Sure, EM is still useful, I use it in my work, but in the end, it all boils down to QM.

[-] scubbo@lemmy.ml 12 points 1 year ago

"X depends on or is built up on Y" does not imply "X is Y". Concepts, laws, techniques, etc. can depend or be higher-order expressions of QM without being QM. If you started asking a QM scientist about tensile strength or the Mohs scale they would (rightly) be confused.

Yes, of course. Coloumb and Maxwell had no idea about QM when they were developing their ideas. Not to mention that these higher-order abstractions are just as valid as QM (up to a point, but so is QM). Depening on the application, you'd want to use a different abstraction. EM is perfect for everyday use, as well as all the way down to the microscale.

My point is that EM is explained by QM, and therefore supercedes it. You could use QM to solve every EM problem, it'd just be waaaaay too difficult to be practical.

[-] scubbo@lemmy.ml 6 points 1 year ago

I feel like you're using "supercede" differently to the rest of us. You're getting a hostile reaction because it sounded like you're saying that EM is no longer at all useful because it has been obsoleted (superceded) by QM. Now you're (correctly) saying that EM is still useful within its domain, but continuing to say that QM supercedes it. To me, at least, that's a contradiction. QM extends EM, but does not supercede it. If EM were supercedes, there would be no situation in which it was useful.

[-] SuckMyWang@lemmy.world 3 points 1 year ago* (last edited 1 year ago)

Guys guys, yesterday I ate some hot wings and then shit myself on the way to the toilet 🤣💪💯

Also can you really solve all em equations with qm? I always thought the laws broke down from one to the other? So you’re saying going from em to qm the laws break down but going from qm to em the laws hold up?

[-] Claidheamh@slrpnk.net 6 points 1 year ago* (last edited 1 year ago)

Quantum mechanics didn't supersede electromagnetism. Again, they're different things. Electromagnetism is a fundamental interaction. Whereas quantum mechanics describes the mechanics of quantum particles. Whether those particles are affected by electromagnetic forces or not. It's a description of how they behave at quantum scales.

Coulomb's law has nothing to do with quantum mechanics, it's a description of how macroscopic charged particles interact. What the OP should have said to be correct is:

Awesome to see the similarities between: Newton's law of gravitation and Coulomb's law

I don't know where he got quantum mechanics from.

[-] HiddenLayer5@lemmy.ml 29 points 1 year ago

Coulomb had the last laugh though because Newton's theory has been superseded by relativity.

[-] Batman@lemmy.world 14 points 1 year ago

What was you doing step gravity?

-Time, probably

[-] itslilith@lemmy.blahaj.zone 12 points 1 year ago

So has Coulomb's theory

[-] Melatonin@lemmy.dbzer0.com 13 points 1 year ago

If there's anyone who can, please let me know if the similarities between these two formulas imply a relationship between gravity and electrical attraction or hint at a unified theory, or if it's just a coincidence or a consequence of something else.

[-] Claidheamh@slrpnk.net 31 points 1 year ago* (last edited 1 year ago)

The relation between them is that they're both forces that scale with the inverse square of the distance between the objects. Any force that scales with the inverse square of distance has pretty much the same general form.

Another similarity is that both are incomplete, first approximations that describe their respective forces. The more complete versions are Maxwell's laws for electromagnetism and General Relativity for gravity.

[-] Magickmaster@feddit.de 18 points 1 year ago

There's some relation in that they both act on fields, but the things that affect those fields are very different (higgs bosons and electrons respectively) and the relationship between all that for an 'unified theory' is a topic of much research. IANAP though (not a physicist)

[-] Tlaloc_Temporal@lemmy.ca 3 points 1 year ago

Are higgs bosons supposed to be gravitons? I think you're confused about how some particles aquire some of their mass, and how all mass behaves.

[-] gentooer@programming.dev 9 points 1 year ago

Electromagnetism and gravity are both mediated by massless bosons; photons and gravitons respectively. This is why both forces follow the inverse square law.

[-] Tlaloc_Temporal@lemmy.ca 8 points 1 year ago

I don't think there's any evidence for gravitons yet, and gravity hasn't been quantized. I'd say it's this similarity that's the best argument of quantum gravity, not the other way around.

[-] gentooer@programming.dev 3 points 1 year ago

Fair. The masslessness of the bosons that should mediate gravity, along with them being spin-2, can however be deduced from the properties of gravitational waves.

[-] tias@discuss.tchncs.de 3 points 1 year ago* (last edited 1 year ago)

We know that gravity is a wave that travels at the speed of light, this has been experimentally measured many times. If it is also quantized (a very reasonable ~~symptom~~ hypothesis since everything else that we've ever seen is) then by definition there are particles that carry gravity.

If gravity is continuous then we would end up with something like the ultraviolet catastrophe but for gravity.

[-] Tlaloc_Temporal@lemmy.ca 1 points 1 year ago

Hmm, I hadn't considered an "ultragravity catastrophe". I wonder if this could accout for dark energy or the supposed inflatons? Probably not, the catastrophe suggests infinite energy, not just lots of energy, eh?

The ultraviolet catastrophe was averted due to the discreet nature of electrons though, and I don't recall gravity behaving as a blackbody radiator anyway. Would this come into effect at horizons?

[-] tias@discuss.tchncs.de 3 points 1 year ago* (last edited 1 year ago)

Sorry, I think I came off as too confident in my previous comment. I'm quite sure about my first paragraph but the rest is just speculation from an amateur.

If I would risk speculating even further though, there's some similarity in the sense that infinities indicate a problem. In the ultraviolet catastrophe the infinity arises from the energy of arbitrarily short EM wavelengths. With gravity it arises in the density of black holes. It seems unreasonable that it would actually be infinite, and it's possible that quantization of gravity plays a part in preventing that from happening.

[-] fred@lemmy.ml 6 points 1 year ago

massless bosons

Why do I feel like I've been insulted

[-] Gabu@lemmy.world 8 points 1 year ago

The most accepted theory among physicists is that "shit's crazy, yo".

[-] trustnoone@lemmy.sdf.org 7 points 1 year ago

There is one thing particularly interesting, and that is that the inverse square laws appears again. It appears in the electrical laws for instance.

That is electricity also exerts forces inverse to the square of distance with charges. One thinks perhaps inverse square distance has some deep significance, maybe gravity and electricity are different aspects of the same thing

...

Today our theory of physics, laws of physics are a multitude of different parts and pieces that don't fit together very well. We don't understand the one in terms of the other. We don't have one structure that it's all deduced we have several pieces that don't quite fit yet.

And that's the reason in these lectures instead of telling you what the law of physics is I talk about the things that's common in the various laws because we don't understand the connection between them.

But what's very strange is that there is certain things that's the same in both

Richard Feynman and 45:48 https://youtu.be/-kFOXP026eE?si=hAIvDhWVGxMOvEi1

[-] Claidheamh@slrpnk.net 3 points 1 year ago* (last edited 1 year ago)

Always upvote Feynman. Got me through some tough times in undergrad.

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[-] Pher@lemmy.world 6 points 1 year ago

It's really simple, they are both radial fields with a 1/r potential, thus a 1/r² force. Newtonian gravity is just a weak field approximation of general relativity, where you have very different equations, for example Einsteins field equations.. One electric charge creates an electric field, and another charge will interact with it, but the motion itself still depends on the mass of the second charge. Matter instead curves spacetime itself, and the curved spacetime tells matter how to move. Source: MS in physics.

[-] Pinklink@lemm.ee 4 points 1 year ago

Doubtful but interesting thinking. It’s actually a rather simple equation that explains how two equally weighted forces affect one another over distance. The numerator expresses that both forces carry equal weight in the interaction (if they are both the same kind of force, eg gravity or electromagnetism, this makes sense) and they are constructive interactions (both add to the intensity of the interaction) hence multiplying one by the other. The denominator just indicates that the distance between the two things exponentially degrades the force at a power of 2, since the force is spreading out in 2 dimensions (imagine a cone starting at one point and extending to the second, so that when you reach the second point the force is spread across the cross section of that cone, but the only part of the force affecting that second point is the part that touches it).

[-] NocturnalMorning@lemmy.world 11 points 1 year ago

Now that's just not fair, Coulomb was born way after Newton. At least make Newton a zombie for realism.

[-] imgprojts@lemmy.ml 11 points 1 year ago

Newton: "FagMad!"

Coulumb: "Fuckyouare!"

this post was submitted on 05 Nov 2023
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