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[-] owenfromcanada@lemmy.world 5 points 4 days ago

For those not wanting to click, there are two questions.

  1. What is the length of x?

1000010208

  1. Can you:

i) Divide a square into five rectangles such that no two rectangles share an entire side in common – i.e. the sides of abutting rectangles never start and finish at the same points? (The rectangles do not need to be the same size or shape.)

ii) Divide an 11 x 11 square into five rectangles in such a way that the ten side lengths are the whole numbers from 1 to 10? Hint: if you have solved part i) use this arrangement of rectangles.

[-] propter_hog@lemmygrad.ml 2 points 3 days ago* (last edited 3 days ago)

From a cursory glance of 1.), it seems to follow that

spoilerx = 0

The outer triangle has sides 8, 5, and 3. This doesn't form a triangle.

Edit: bah, never mind. I looked at the solution, and I'm a dunce. x = 1 because 4 - 3 = 1.

[-] Xavienth@lemmygrad.ml 1 points 3 days ago

I find the triangle problem a bit silly. There's a clever insight to easily solve it, but the alternative, systematic approach is not exactly high-level knowledge.

this post was submitted on 18 Feb 2025
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