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[-] LovableSidekick@lemmy.world 1 points 2 months ago

Assigning a value of 5 to pi, although ludicrous IRL, doesn't affect the problem. Plug the values into the equation and it will still give an answer that's correct in context.

[-] bss03@infosec.pub 0 points 2 months ago

Do cylinders even exist in metrics where pi = 5 ?

[-] LovableSidekick@lemmy.world 0 points 2 months ago

Technically no, because pi equals pi not 5. But you can approximate its value as 3 or 5 or whatever you want, knowing it's not exact and that your result will only be an approximation. I mean you could also ask how long light takes to reach us from Alpha Centauri if the speed of light is 1000 mph. It's not, but if you make that a condition of the problem you can do the calculation just fine.

[-] bss03@infosec.pub 1 points 2 months ago

I think that reason would make it "Technically Yes", since False (pi = 5) implies False (cylinders exist) is (vacuously) True ("absurd premise").

[-] Shardikprime@lemmy.world -1 points 2 months ago

Yes. The 3d shape existence is not affected by changing pi values

[-] bss03@infosec.pub 0 points 2 months ago

Cause it's just a (n-1)-dimensional ball extruded along the remaining axis, or do all 3d shapes exist on (nearly) all 3d metrics?

[-] Shardikprime@lemmy.world 1 points 2 months ago

Mostly because the actual pi values can vary in between non/euclidean geometries. Within extremely strong gravitational fields, spacetime becomes highly non euclidean, affecting the C/d ratio of an actual circle, so I'd wager this would affect pi as well

[-] Opisek@lemmy.world 0 points 2 months ago

For the benefit of doubt, maybe the test is from an alternate dimension that doesn't use euclidean space.

[-] OrteilGenou@lemmy.world 0 points 2 months ago

I've been there, I think, but it was really difficult to triangulate my location and confirm

[-] ouRKaoS@lemmy.today 1 points 2 months ago

That's because you were supposed to rhombusulate, not triangulate.

this post was submitted on 17 May 2025
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