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this post was submitted on 01 Jul 2025
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You could arrange them that way, but the goal is to find the way to pack the small squares in a way that results in the smallest possible outer square. In the solution shown, the length of one side of the outer square is just a bit smaller than 12. If you pack them normally, the length would be ~~larger than~~ exactly 12. (1 = the length of one side of the smaller squares.)