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submitted 6 months ago* (last edited 6 months ago) by fossilesque@mander.xyz to c/science_memes@mander.xyz
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[-] hydroptic@sopuli.xyz 78 points 6 months ago* (last edited 6 months ago)

And mathematicians divide by multiplying!

In formal definitions of arithmetics, division can be defined via multiplication: as a simplified example with real numbers, because a ÷ 2 is the same as a × 0.5, this means that if your axioms support multiplication you'll get division out of them for free (and this'll work for integers too, the definition is just a bit more involved.)

Mathematicians also subtract by adding, with the same logic as with division.

[-] bort@feddit.de 14 points 6 months ago

if your axioms support multiplication you’ll get division out of them for free

this is true... except when it isn't.

In mathematics, rings are algebraic structures that generalize fields: multiplication need not be commutative and multiplicative inverses need not exist

https://en.wikipedia.org/wiki/Ring_(mathematics)

[-] hydroptic@sopuli.xyz 12 points 6 months ago* (last edited 6 months ago)

Yeah I should maybe just have written

if your axioms support multiplication you’ll get division out of them for free^*^

^*^certain terms and conditions may apply. Limited availability in some structures, North Korea, and Iran. Known to the state of California to cause cancer or reproductive toxicity

[-] meowMix2525@lemm.ee 12 points 6 months ago* (last edited 6 months ago)

Right. The cells are dividing in half, which would be represented in math form by 1/0.5 = 2. Dividing by one half is the same thing as multiplying by 2, and division in general is really just a visually simplified way to multiply by a fraction of 1.

Any time you divide by some fraction of 1, you will necessarily end up with a larger number because you're doubling that division which reverses it back into multiplication, much in the same way as a negative x negative = positive. If that makes sense.

A mathematician would not be bothered by this. A high schooler taking algebra I might be though, if you phrased it the same way this post did.

[-] kogasa@programming.dev 7 points 6 months ago

a/b is the unique solution x to a = bx, if a solution exists. This definition is used for integers, rationals, real and complex numbers.

Defining a/b as a * (1/b) makes sense if you're learning arithmetic, but logically it's more contrived as you then need to define 1/b as the unique solution x to bx = 1, if one exists, which is essentially the first definition.

[-] Artyom@lemm.ee 4 points 6 months ago

That's me, a degree-holding full time computer scientist, just learning arithmetic I guess.

Bonus question: what even is subtraction? I'm 99% sure it doesn't exist since I've never used it, I only ever use addition.

[-] kogasa@programming.dev 3 points 6 months ago

Addition by the additive inverse.

[-] Artyom@lemm.ee 1 points 6 months ago

Now you just replaced one incalculable thing with a different incalculable thing.

[-] kogasa@programming.dev 1 points 6 months ago
[-] Artyom@lemm.ee 2 points 6 months ago

Computers don't subtract, and you can't just add a negative, a computer can't interpret a negative number, it can only store a flag that the number is negative. You need to use a couple addition tricks to subtract to numbers to ensure that the computer only has to add. It's addition all the way down.

[-] kogasa@programming.dev 1 points 6 months ago

What does this have to do with computers?

[-] hydroptic@sopuli.xyz 1 points 6 months ago* (last edited 6 months ago)

what even is subtraction?

It's just addition wearing a trench coat, fake beard and glasses

[-] hydroptic@sopuli.xyz 0 points 6 months ago* (last edited 6 months ago)

Defining a/b as a * (1/b) makes sense if you’re learning arithmetic

The example was just to illustrate the idea not to define division exactly like that

[-] platypus_plumba@lemmy.world 3 points 6 months ago

Cells: 🫣🫨😢

this post was submitted on 25 Feb 2024
722 points (96.3% liked)

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