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Behold, a square (sopuli.xyz)

submitted 3 weeks ago by hydroptic@sopuli.xyz to c/science_memes@mander.xyz

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[-] Doll_Tow_Jet-ski@fedia.io 11 points 3 weeks ago

What are the 4 sides?

[-] Assman@sh.itjust.works 17 points 3 weeks ago

The black lines

[-] CodexArcanum@lemmy.world 8 points 3 weeks ago

The semi-circle is one side, then the 2 straight edges, and the arc between them is the 4th side.

[-] Doll_Tow_Jet-ski@fedia.io 7 points 3 weeks ago

That's what I thought. The only way on which this has four sides is if the semi -circle is a side. But if that's the case, then I don't know wha the definition of "side" is

[-] bstix@feddit.dk 10 points 3 weeks ago

Knock knock. Do you have a moment to discuss non-euclidean geometry?

[-] Doll_Tow_Jet-ski@fedia.io 10 points 3 weeks ago

/slams door

[-] UrLogicFails@beehaw.org 5 points 3 weeks ago

Someone may want to double-check my math on this one, but the length of the sides will be dependant on the radius of the smaller circle

ϴ=π+1-√(π^2+1), l=(2π-ϴ)r_1, l is the length of the sides. r_1 is the radius of the smaller circle

[-] m0darn@lemmy.ca 4 points 3 weeks ago* (last edited 3 weeks ago)

I look at your diagram and see:

ϴ= L/(L+R)

And

2π-ϴ = L/R

I solved those (using substitution, then the quadratic formula) and got

L= π-1 ± √(1+π²) ~= 5.44 or -1.16

Whether or not a negative length is meaningful in this context is an exercise left to the reader

Giving (for L=5.44):

ϴ~= 0.845 ~~48.4°

I'm surprised that it solved to a single number, maybe I made a mistake.

[-] UrLogicFails@beehaw.org 3 points 3 weeks ago

That lines up pretty similarly with what I found also. The angle should be a constant since there is only one angle where the relationship would be true. I just left it in terms of π because I try to avoid rounding.

Having said that, L would be a ratio of r; which I think lines up with what you found as well.