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[-] cholesterol@lemmy.world 11 points 2 days ago

Paradoxes aside, if you're given multiple choices without the guarantee that any of them are correct, you can't assign a chance of picking the right one at random anyway.

[-] ImplyingImplications@lemmy.ca 19 points 2 days ago

This seems like a version of the Liar paradox. Assume "this statement is false" is true. Is the statement true or false?

There are a bunch of ways to break the paradox, but they all require using a system that doesn't allow it to exist. For example, a system where truth is a percentage so a statement being 50% true is allowed.

For this question, one way to break the paradox would be to say that multiple choice answers must all be unique and repeated answers are ignored. Using that rule, this question only has the answers a) 25%, b) 60%, and c) 50%, and none of them are correct. There's a 0% chance of getting the correct answer.

[-] lmuel@sopuli.xyz 6 points 2 days ago
[-] zkfcfbzr@lemmy.world 5 points 2 days ago* (last edited 2 days ago)

It is 33% if the answer itself is randomly chosen from 25%, 50%, and 60%. Then you have:

If the answer is 25%: A 1/2 chance of guessing right

If the answer is 50%: A 1/4 chance of guessing right

If the answer is 60%: A 1/4 chance of guessing right

And 1/3*1/2 + 1/3*1/4 + 1/3*1/4 = 1/3, or 33.333...% chance

If the answer is randomly chosen from A, B, C, and D (With A or D being picked meaning D or A are also good, so 25% has a 50% chance of being the answer) then your probability of being right changes to 37.5%.

This would hold up if the question were less purposely obtuse, like asking "What would be the probability of answering the following question correctly if guessing from A, B, C and D randomly, if its answer were also chosen from A, B, C and D at random?", with the choices being something like "A: A or D, B: B, C: C, D: A or D"

[-] thatradomguy@lemmy.world 8 points 2 days ago

I see 25% twice so my bet is on 50%.

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[-] Commiunism@beehaw.org 13 points 2 days ago

50/50, you either guess it right or you dont

[-] deur@feddit.nl 12 points 2 days ago* (last edited 2 days ago)

If you suppose a multiple choice test MUST ONLY have one correct answer:

  1. Eliminate duplicate 25% answers

  2. You are left with 60% and 50% as potential answers to this question.

  3. C is the answer

If you were to actually select an answer at random to this question while believing the above, you would have a 50% chance of answering 25%.

It is obvious to postulate that: for all multiple choice questions with no duplicate answers, there is a 25% chance of selecting the correct answer.

However as you can see, in order to integrate the answer being C with the question itself, we have to destroy the constraints of the solution and treat the duplicate 25% answers as one sum correct answer.

Do you choose to see the multiple choice answer space as an expression of the infinite space of potential free form answers? Was the answer to the question itself an expression of multiple choice probability or was it the answer from the free form answer space condensed into the multiple choice answer space?

The question demonstrates arriving at different answers between inductive and deductive reasoning. The answer depends on whether we are taking the answers and working backwards or taking the question and working forwards. The question itself forces the inductive reasoning strategy to falter at the duplicate answers, leading to deductive reasoning being the remaining strategy. Some may choose to say "there is no answer" in the presence of needing to answer a question that only has an answer because we are forced to pick one option, and otherwise would be invalid. Some may choose to point out it is obviously a paradox.

[-] SculptusPoe@lemmy.world 11 points 2 days ago* (last edited 2 days ago)

The answer is not available. The answer is 0 Percent. Each answer, if chosen, would be incorrect. If 0% was an answer, it would be the correct one despite being a 25% chance. Of course, if one 25% was there, that would be the correct answer.

[-] FaceDeer@fedia.io 11 points 2 days ago

But if you did randomly choose the 0% option, you'd be correct. So if one of the possible answers was 0% the correct answer would be 25%.

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[-] gnutrino@programming.dev 9 points 2 days ago* (last edited 2 days ago)

This only produces a paradox if you fall for the usual fallacy that "at random" necessarily means "with uniform probability".

For example, I would pick an answer at random by rolling a fair cubic die and picking a) if it rolls a 1, b) on a 2, d) on a 3 or c) otherwise so for me the answer is c) 50%.

However, as it specifies that you are to pick at random the existence, uniqueness and value of the correct answer depends on the specific distribution you choose.

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this post was submitted on 06 May 2025
627 points (97.4% liked)

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