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submitted 1 week ago by Cyniez@lemmy.world to c/asklemmy@lemmy.ml
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[-] transientpunk@sh.itjust.works 48 points 1 week ago* (last edited 1 week ago)
[-] Rentlar@lemmy.ca 68 points 1 week ago* (last edited 1 week ago)

Note that the problem states that the outer shape is a quarter circle, information not provided in OP's question.

Knowing it is a quarter circle is important because it allows us to validate that the bottom-right angle is 90 degrees.

[-] flicker@lemmy.dbzer0.com 3 points 1 week ago

I actually came to the comments to see if we had this information! Thanks.

[-] gezginorman@lemmy.ml 2 points 1 week ago

but does it have to be a given, or can we actually prove that it has to be

[-] bstix@feddit.dk 17 points 1 week ago

It has to be given, otherwise there would be infinitely many solutions.

You would need some other information to link the line segment X to the rest of the figure.

[-] olosta@lemmy.world 4 points 1 week ago

The explanation don't explain why AE must be a diameter of the circle. What makes that obvious?

[-] Deme@sopuli.xyz 11 points 1 week ago
[-] tehn00bi@lemmy.world 3 points 1 week ago

How have I had years of math and not seen this? I mean, it’s not super useful for me, but I would have thought I would have seen something like this in pre calculus at least.

[-] Treczoks@lemmy.world 2 points 1 week ago

Geometry, class six or seven.

[-] maxprime@lemmy.ml 1 points 1 week ago

I teach this to my grade 9 class in Canada. It’s on the curriculum.

[-] tehn00bi@lemmy.world 1 points 1 week ago

Nice. I have no recollection of seeing this before.

[-] maxprime@lemmy.ml 1 points 1 week ago

Tbf most Canadian grade 9 teachers skip it.

[-] breakingcups@lemmy.world 3 points 1 week ago

Wow, that's cool

[-] newnton@sh.itjust.works 2 points 1 week ago
[-] ocean@lemmy.selfhostcat.com 1 points 1 week ago

Tats so cool! Did you just do that or find it?

this post was submitted on 25 Mar 2025
122 points (87.7% liked)

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