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[-] mexicancartel@lemmy.dbzer0.com 5 points 6 months ago

Adding 3 on both sides

3-3=3+3

0 = 6

1•0 = 6

1 = 6/0

1 = inf

Multiplying e^(iπ) on both sides,

e^(iπ) = - inf

iπ = ln|-inf|

π = ln|-inf| ÷ i

[-] Maalus@lemmy.world 2 points 6 months ago
[-] mexicancartel@lemmy.dbzer0.com 2 points 6 months ago

Like if everything else is true.

1/0 can be infinity as a limiting case but not always. So imma use what i like since i also took ln|x| (took mod out of nowhere just to make it positive)

[-] emergencyfood@sh.itjust.works 0 points 6 months ago

Division is repeated subtraction. How many times can you subtract 0 from 1?

[-] hemko@lemmy.dbzer0.com 1 points 6 months ago* (last edited 6 months ago)

I gotta say second half of that goes over my head, but I raise my hat to you

[-] mexicancartel@lemmy.dbzer0.com 2 points 6 months ago

I remember you. You saved me from rickroll on xkcd

[-] hemko@lemmy.dbzer0.com 2 points 6 months ago
[-] huf@hexbear.net 0 points 6 months ago

it starts out okay but 6/0 is not inf.

[-] mexicancartel@lemmy.dbzer0.com 2 points 6 months ago

Its just the joke i take watever i want. There is | | inside log which is just made up. 6/x as x->0 is infinity though so i'mma use that

this post was submitted on 17 Apr 2024
781 points (98.0% liked)

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