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[-] jerkface@lemmy.ca 14 points 1 day ago* (last edited 1 day ago)

Doesn't this also imply that i == 1 because CB has zero length, forcing AC and AB to be coincident? That sounds like a disproving contradiction to me.

[-] xor@lemmy.blahaj.zone 7 points 1 day ago

I think BAC is supposed to be defined as a right-angle, so that AB²+AC²=CB²

=> AB+1²=0²

=> AB = √-1

=> AB = i

[-] jerkface@lemmy.ca 2 points 21 hours ago

I mean, I see that's how they would have had to get to i, but it's not a right triangle.

[-] Knock_Knock_Lemmy_In@lemmy.world 1 points 9 hours ago

i is at a right angle (pi/2) to 1 by definition.

this post was submitted on 30 Oct 2024
386 points (97.3% liked)

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